m-3/2m-m^2-16/m*1/3m+12

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Solution for m-3/2m-m^2-16/m*1/3m+12 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

m-m^2-((3/2)*m)-(((1*(16/m))/3)*m)+12 = 0

m-m^2+(-3/2)*m-16/3+12 = 0

20/3-m^2-1/2*m = 0

DELTA = (-1/2)^2-(-1*4*20/3)

DELTA = 323/12

DELTA > 0

m = ((323/12)^(1/2)+1/2)/(-1*2) or m = (1/2-(323/12)^(1/2))/(-1*2)

m = ((323/12)^(1/2)+1/2)/(-2) or m = (1/2-(323/12)^(1/2))/(-2)

m in { ((323/12)^(1/2)+1/2)/(-2), (1/2-(323/12)^(1/2))/(-2) }

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